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(-2)=-F^2-9F
We move all terms to the left:
(-2)-(-F^2-9F)=0
We add all the numbers together, and all the variables
-(-F^2-9F)-2=0
We get rid of parentheses
F^2+9F-2=0
a = 1; b = 9; c = -2;
Δ = b2-4ac
Δ = 92-4·1·(-2)
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{89}}{2*1}=\frac{-9-\sqrt{89}}{2} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{89}}{2*1}=\frac{-9+\sqrt{89}}{2} $
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